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## GAH CALCULUS! derive/int e and logs

This is a discussion on GAH CALCULUS! derive/int e and logs within the General Off Topic+ forums, part of the QJ.net Forum Miscellaneous category; HALP integrate e^(.5*ln(x)) dx -= Double Post =- integrate ln(x)/x dx...

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1. ## GAH CALCULUS! derive/int e and logs

HALP

integrate e^(.5*ln(x)) dx
-= Double Post =-
integrate ln(x)/x dx

2. integrate ln(x)/x dx

Code:
```ln(x)=u
du=1/x dx

integrate u du
1/2(u^2)

replace u <-- I sometimes forget this step >_<
(1/2)[ln(x)^2] + C```
integrate e^(.5*ln(x)) dx
Code:
```integrate e^(ln [sqrt x]) dx <-- log rule
integrate [sqrt x] dx <-- e and ln cancels each other out
(2/3)(x^[3/2]) + C```

3. oh thank you so much!!!!!! nao only 10 moar problems.....
-= Double Post =-
wait... whered tht 2 come from?

4. Originally Posted by Da_MerV
wait... whered tht 2 come from?
a little more specific?

5. integrate u du
1/2(u^2)

thats where im fuzzy

6. u = u^1

then the integration should look like this
Code:
```[u^(1+1)]/[1+1]

[u^2]/2```

7. Don't feel like working it out, but to integrate, you must do the opposite of differentiating. So, for the first one, according to the chain rule, you first have to divide by the derivative of .5lnX, then integrate, knowing that e is it's own integral/derivative.

8. k thx got it
wow im dumb
actually just really tiredd

9. No problem. Good Luck

For some reason, integration is easier for me than differentiating

10. GRRRRRRR MOAR HALP PLZ
intg (x^2)(e^(x^3))dx
edit: nvm got it

11. it should be (1/3)e^[x^3] + C

12. hey still cant get

integrate e^(.5*ln(x)) dx

and its the last one i have to do

13. Check my first post.

14. Yes Done!!!!!! Thank You Anubis!

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