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## more math help

This is a discussion on more math help within the General Off Topic+ forums, part of the QJ.net Forum Miscellaneous category; 3x - 3/x(x-3) why cant you cancel out the x after the 3 with the x on the denominator before ...

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1. ## more math help

3x - 3/x(x-3) why cant you cancel out the x after the 3 with the x on the denominator before the (x-3)? is it cause the one on top is substracting while one on bottom is multyplying?

another question, 1/(1 + 1/2) those perenthesies arent there I just added them cause its not 1 plus one half but the one is above an entire denominator. why is the awnser 2/3 and not 3? cant you solve those kinds of problems by making the equation 1 (one voer one) + 2 (one over one half)?

and lastly for now, if you have a whole numerator of numebrs such as a^4 + b^3 + c^5/A^3+b^2+c^3 cabt you just subtract the denominator exponent from the numerator ones making it a+b+c^2 and if that is the case can you only do that if they numebrs corresponding are doing the same thing like adding/suibtracting or multiplying or cna you mix it like if the bottom had a^3b^2 and not a^3+b^2?
-= Double Post =-
oh and I forgot to add, if finding the long leg of a triangle is a suqared plus b squared equals c squared, what if its not a triangle with a straight 90 degree legs, but has two cross (z axis) ones?

2. Problem 1

3x - 3/x(x - 3) can be written as
```          3x               3
------   -    ------
x(x-3)         x(x-3)```

For the first number, you can cancel out both the top and bottom 'x'. For the second number there is no 'x' on top, so you can't cancel the bottom 'x' out. This will mean the 2 denominators won't be the same and you can't subtract them.

Problem 2

1/(1 + 1/2) is the same as 1/(3/2)
When you divide by a fraction, you multiply by the reciprocal.
So it becomes 1 * 2/3 = 2/3

Problem 3

Can't understand what you are saying.

3. antoher one (sorry): why is it I can multiply 3^2 times 2^2 by making it 6^2 but when I divide that number, 9/4 is not the same as 3-2=1^2?

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